A body is dropped from a height of $39.2 m$ . After it crosses the half distance, the acceleration due to gravity comes to an end. Then the body will hit the ground with a velocity of $($ Take $g = 9.8 {ms}^{- 2})$

19.6 m/s

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20 m/s

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1.96 m/s

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196 m/s

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Solution

The correct option is A $19.6 m/s$
Height $h = 39.2 m$
Also, $u = 0$ and $g = 9.8 {m/s}^{2}$
Now, from equation of motion
$\Rightarrow v^{2} = u^{2} + 2 a s$

After crossing half distance, the acceleration due to gravity stops acting
So $h = \frac{39.2}{2} = 19.6 m$

$\Rightarrow v^{2} = u^{2} + 2 a h$

$\Rightarrow v^{2} = 2 \times 9.8 \times 19.6 = (19.6)^{2}$

$\Rightarrow v = 19.6 m/s$

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A body is dropped from a height of 39.2 m. After it crosses the half distance, the acceleration due to gravity comes to an end. Then the body will hit the ground with a velocity of (Take g=9.8 ms−2)

The correct option is A 19.6 m/sHeight h=39.2 m Also, u=0 and g=9.8 m/s2 Now, from equation of motion ⇒v2=u2+2as After crossing half distance, the acceleration due to gravity stops acting So h=39.22=19.6 m ⇒v2=u2+2ah ⇒v2=2×9.8×19.6=(19.6)2 ⇒v=19.6 m/s

A body is dropped from a height of $39.2 m$ . After it crosses the half distance, the acceleration due to gravity comes to an end. Then the body will hit the ground with a velocity of $($ Take $g = 9.8 {ms}^{- 2})$