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Question
A body is dropped from the top of a tower. Simultaneously, another body is projected vertically up from the tower. If they meet with equal speed V, then initial velocity of the body projected upwards is:
A body is dropped from the top of a tower. Simultaneously, another body is projected vertically up from the tower. If they meet with equal speed V, then initial velocity of the body projected upwards is:
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Solution
The correct option is D V√2
As the second body goes up and comes down and meets the first body, the displacement of the second body is same as that of the first body.
And also when the second body reaches the point of projection, its speed will be same as the speed of projection, let it be u.
For first body, initial speed is zero.
V2=2gh
For second body,
V2−u2=−2gh
From these two equations,
2V2−u2=0
⇒u=2√V
As the second body goes up and comes down and meets the first body, the displacement of the second body is same as that of the first body.
And also when the second body reaches the point of projection, its speed will be same as the speed of projection, let it be u.
For first body, initial speed is zero.
V2=2gh
For second body,
V2−u2=−2gh
From these two equations,
2V2−u2=0
⇒u=2√V
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