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Question

A body is moving with velocity 30 m/s. A variable force a N is applied at t=0 s on the body such that it increases it's velocity to 90 m/s at t=4 s in same direction. The variation of force with time is shown in graph.

If mass of body is 10 kg, find the value of a (shown in graph)

A
150 N
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B
100 N
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C
50 N
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D
125 N
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Solution

The correct option is A 150 N

We know
Impulse imparted by force for (t=0) s to (t=4) s= {area under (F-t) graph from (t=0 s) to (t=4 s)}
Also impulse imparted by force =Δmv
a×4=mΔv
4a=10×[9030]
4a=10×60
a=150 N

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