1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# A body is moving with velocity 30 m/s. A variable force a N is applied at t=0 s on the body such that it increases it's velocity to 90 m/s at t=4 s in same direction. The variation of force with time is shown in graph. If mass of body is 10 kg, find the value of a (shown in graph)

A
150 N
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
100 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
50 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
125 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is A 150 N We know Impulse imparted by force for (t=0) s to (t=4) s= {area under (F-t) graph from (t=0 s) to (t=4 s)} Also impulse imparted by force =Δmv ⇒a×4=mΔv 4a=10×[90−30] 4a=10×60 a=150 N

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Summary and Misconceptions
PHYSICS
Watch in App
Join BYJU'S Learning Program