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Question

A body of mass 1 kg is projected from ground at an angle 30 with horizontal on a level ground at a speed 50 m/s. The magnitude of change in momentum of the body during its flight is (g=10 m/s2)

A
50 kg ms1
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B
100 kg ms1
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C
25 kg ms1
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D
Zero
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Solution

The correct option is A. 50 kg ms1.

We know that in the horizontal plane, the initial velocity of projectile = final velocity of the projectile


pi=mucosθ^i+musinθ^j

pf=mucosθ^imusinθ^j

Δp=pfpi=2musinθ^j

|Δp|=2musinθ

=2×1×50×12=50 kg ms1

Alternative: In the horizontal direction momentum does not change,
Δ Px=0
In vertical direction
ΔPy=(musinθ)(musinθ) (Take downward as positive)
=2musinθ downward
=2×1×50×12=50 kg ms1


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