Question

A body of mass 2 kg having a velocity of $2\frac{m}{s}$ is brought to rest within a distance of 2m by a constant force acting on it. Find the force acting on the body?

• A. 8 N
• B. 1 N
• C. 4 N
• D. 2 N

Answer 1

The correct option is D 2 N

$v^2=u^2+2aS$
(v is the final velocity, u is the initial velocity and a is the acceleration)

v = 0m/s; as the object comes to rest

u = 2 m/s and s = 2m

Thus, $a=-1m/s^2$
The magnitude of acceleration is $1m/s^2$

F = ma;

m= 2kg

Force acting on the body is

$F=2\times 1=2N$