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Law of Conservation of Mechanical Energy

A body of mas...

Question

A body of mass 2 kg is thrown upward with an energy 490 J. The height at which its kinetic energy would become half of its initial kinetic energy will be $[g = 9.8 m / s^{2}]$

35 m

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25 m

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12.5 m

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10 m

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Solution

The correct option is C
12.5 m

If the kinetic energy would become half, then Potential energy = $\frac{1}{2}$ (Initial kinetic energy)

$\Rightarrow m g h = \frac{1}{2} [490] \Rightarrow 2 \times 9.8 \times h = \frac{1}{2} [490] \Rightarrow h = 12.5 m$

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Similar questions

A body of mass 2 kg is thrown upward with an energy 490 J. The height at which its kinetic energy would become half of its initial kinetic energy will be $[g = 9.8 m / s^{2}]$

Q. A body of mass

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A body of mass 2 kg is thrown upward with an energy 490 J. The height at which its kinetic energy would become half of its initial kinetic energy will be [g=9.8m/s2]

The correct option is C 12.5 m If the kinetic energy would become half, then Potential energy = 12 (Initial kinetic energy) ⇒mgh=12[490]⇒2×9.8×h=12[490]⇒h=12.5 m

A body of mass 2 kg is thrown upward with an energy 490 J. The height at which its kinetic energy would become half of its initial kinetic energy will be $[g = 9.8 m / s^{2}]$

The correct option is C
12.5 m

If the kinetic energy would become half, then Potential energy = $\frac{1}{2}$ (Initial kinetic energy)

$\Rightarrow m g h = \frac{1}{2} [490] \Rightarrow 2 \times 9.8 \times h = \frac{1}{2} [490] \Rightarrow h = 12.5 m$