A body of mass $M$ collides against a wall with velocity $V$ and rebounds with the same speed. Its magnitude of change in momentum is:

0

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M V

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2 M V

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\frac{M V}{2}

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Solution

The correct option is C $2 M V$
Given that the body of mass M, velocity V rebounds with the same speed.
Change of momentum $= M \times$ (Change in velocity)
$= M (V - (- V)) = 2 M V$
Thus, the change in momentum of the rebounding ball is $2 M V$ .

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A body of mass M collides against a wall with velocity V and rebounds with the same speed. Its magnitude of change in momentum is:

The correct option is C 2MVGiven that the body of mass M, velocity V rebounds with the same speed. Change of momentum =M× (Change in velocity)=M(V−(−V))=2MVThus, the change in momentum of the rebounding ball is 2MV.

A body of mass $M$ collides against a wall with velocity $V$ and rebounds with the same speed. Its magnitude of change in momentum is:

The correct option is C $2 M V$
Given that the body of mass M, velocity V rebounds with the same speed.
Change of momentum $= M \times$ (Change in velocity)
$= M (V - (- V)) = 2 M V$
Thus, the change in momentum of the rebounding ball is $2 M V$ .