A body projected at an angle with the horizontal has a range 300 m. If the time of flight is 6 s, then the horizontal component of velocity is :

30 m s^{- 1}

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50 m s^{- 1}

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40 m s^{- 1}

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45 m s^{- 1}

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30 \sqrt{2} m s^{- 1}

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Solution

The correct option is B $50 m s^{- 1}$
Given, $R = 300 m$ and $t = 6 s$
We know that,
$R = u_{n} \times t$
$u_{n} = \frac{R}{t}$
$u_{n} = \frac{300}{6}$
$u_{n} = 50 m s^{- 1}$

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