A body released from certain height reaches the ground after $^{'} t^{'}$ seconds. The time taken to reach half height is

t / 2

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t / \sqrt{2}

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\sqrt{2} t

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N o n e

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Solution

The correct option is A $t / 2$
Total time $= t$ sec. (as given)
The total time is taken for the height $(h)$
Thus the height is decreased to $h / 2$
The time taken to reach half height $= t / 2$ .

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A body released from certain height reaches the ground after ′t′ seconds. The time taken to reach half height is

The correct option is A t/2Total time =t sec. (as given)The total time is taken for the height (h) Thus the height is decreased to h/2The time taken to reach half height =t/2.

A body released from certain height reaches the ground after $^{'} t^{'}$ seconds. The time taken to reach half height is

The correct option is A $t / 2$
Total time $= t$ sec. (as given)
The total time is taken for the height $(h)$
Thus the height is decreased to $h / 2$
The time taken to reach half height $= t / 2$ .