Question

A body starts from rest and travels with uniform acceleration such that it covers $8m$ during the $2^{nd}$ second. The distance it would travel during the $5^{th}$ second is

• A. $20m$
• B. $24m$
• C. $28m$
• D. $16m$

Answer 1

The correct option is B $24m$

Distance travel in $n^{th}$ second formula is
$s_n=u+\left(\frac{a}{2}\right)(2n-1)$
For $2^{nd}$ second,
$s_2=8=u+\left(\frac{a}{2}\right)(2\times 2-1)$ ----- (1)
For $5^{th}$ second,
$s_5=u+\left(\frac{a}{2}\right)(2\times 5-1)$ ----- (2)
Dividing (2) by (1) and substituting $u=0$, we get
$s_5=24m$