Question

A body starts from rest is moving under a constant acceleration up to 20 s . If it moves $S_1$ Distance in first 10 s, and $S_2$ distance in next 10 s then $S_2$ will be equal to:

• A. $S_1$
• B. $2S_1$
• C. $3S_1$
• D. $4S_1$

Answer 1

The correct option is C $3S_1$

$s_1=0+\frac{1}{2}a(10{)}^2=50a.............(i)$
after $10sv=10a.....\left(ii\right)$
Now $s_2=\left(10a\right)t+\frac{1}{2}a(10{)}^2$
$s_2=\left(10a\right)10+\frac{1}{2}a\left(100\right)$
$s_2=100a+50a=150a=3\left(50a\right)\Rightarrow s_2=3s_1$