A body starts moving with an initial velocity of $5 {m s}^{- 1}$ and an acceleration of $1 {m s}^{- 2}$ . The distance travelled by it in the 5th second is

9.5

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22.5

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50

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10

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Solution

The correct option is A $9.5$ m
Initial velocity $u = 5 m / s$
Acceleration $a = 1 m / s^{2}$
Distance covered in $5 t h$ second, $S_{5} = u + \frac{1}{2} a (2 t - 1)$
where $t = 5 s$
$∴$ $S_{5} = 5 + \frac{1}{2} (2 \times 5 - 1) = 9.5 m$

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