a body whose mass is 6 kg is acted on by a force which changes its velocity from 3 M per second to 5 M per second find the Impulse of Force.if force is active for 2 seconds find the force in Newtons .

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Solution

Impulse is rate of change of momentum = dP/dt
= d/dt(mv)
=m dv/dt
=m(v2 - v1)
= 6(5-3)
=62
=12Ns
And also impulse= force change in time
so force= impulse/time
. =12/2 =6N

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a body whose mass is 6 kg is acted on by a force which changes its velocity from 3 M per second to 5 M per second find the Impulse of Force.if force is active for 2 seconds find the force in Newtons .

Impulse is rate of change of momentum = dP/dt = d/dt(mv) =m dv/dt =m(v2 - v1) = 6(5-3) =6*2 =12Ns And also impulse= force* change in time so force= impulse/time . =12/2 =6N​​​​​​​ ​​​

Impulse is rate of change of momentum = dP/dt
= d/dt(mv)
=m dv/dt
=m(v2 - v1)
= 6(5-3)
=62
=12Ns
And also impulse= force change in time
so force= impulse/time
. =12/2 =6N