Question

A box contains $10$ cards printed first $10$ natural numbers. What is the probability of getting-
(i) an even number
(ii) a multiple of $3$
(iii) multiple of $3$ or $4$
(iv) an odd number
(v) a number between $3$ and $6$
(vi) a number $0$
(vii) a number greater than $10$

Answer 1

Numbers on cards are $1,2,3,4,5,6,7,8,9,10$

$i)$Even Numbers are $2,4,6,8,10$

Probability$=\frac{5}{10}=\frac{1}{2}$

$ii)$Multiple of $3are3,6,9$

Probability$=\frac{3}{10}$

$iii)$Multiple of $3or4are3,4,6,8,9$

Probability$=\frac{5}{10}=\frac{1}{2}$

$iv)$odd number$1,3,5,7,9$

Probability$=\frac{5}{10}=\frac{1}{2}$

$v)$Number between $3and6are4and5$

Probability$=\frac{2}{10}=\frac{1}{5}$

$vi)$ $0$ can't be output so probability is $0$

$vii)$ number greater than $10$ are $0$ so probability is $0$