A box contains coins of 50 paise, 1 rupee and 2 rupees. For 240 coins in the box, the ratio of 50 paise to 1 rupee to 2 rupees is 8 : 17 : 15. How many 1 rupee coins are there in the box ?

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102

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108

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Solution

The correct option is B 102
$L e t n u m b e r o f 50 p a i s e c o i n = a n u m b e r o f 1 R s c o i n = b n u m b e r o f 2 R s c o i n = c ∴ G i v e n a : b : c = 8 : 17 : 15 ∴ b^{'} s p a r t i s \frac{17}{8 + 17 + 15} = \frac{17}{40} ∴ A c t u a l n u m b e r o f b i s \frac{17}{40} \times 240 = 102 ∴ N u m b e r o f 1 R s c o i n i s 102. (A n s)$

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A box contains coins of 50 paise, 1 rupee and 2 rupees. For 240 coins in the box, the ratio of 50 paise to 1 rupee to 2 rupees is 8 : 17 : 15. How many 1 rupee coins are there in the box ?

The correct option is B 102Letnumberof50paisecoin=anumberof1Rscoin=bnumberof2Rscoin=c∴Givena:b:c=8:17:15∴b′spartis178+17+15=1740∴Actualnumberofbis1740×240=102∴Numberof1 Rscoinis102.(Ans)