You visited us 4 times! Enjoying our articles? Unlock Full Access!

Gravitational Force

A boy of mass...

Question

A boy of mass $40 k g$ runs upstairs and reaches the roof at height $8 m$ in $5 s$ . $($ Take $g = 10 m s^{- 2})$ . Calculate the force of gravity acting on the boy.

0 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

400 N

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

40 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $400 N$
$F o r c e = m \times a$ . Given mass is equal to 40Kg and as we are finding force of gravity $a = g$ . Hence $F = 40 \times 10 = 400 N$ .

Suggest Corrections

Similar questions

40 k g

8 m

5 s

(

g = 10 m s^{- 2})

40 k g

8 m

5 s

(

g = 10 m s^{- 2})

A boy of mass 40kg climbs up the stairs and reaches the roof at a height 8m in 5s.Calculate :

1-the force of gravity acting on the boy

2-the work done by him against the gravity

3-the power sent by the boy

(take g=10m 1/s²)

g = 10 m s^{-} 2.

100 g

10 m

(g = 10 m s^{- 2})

Join BYJU'S Learning Program