A boy of mass 50 kg is standing on a weighing machine placed on the floor of a lift. The machine reads his weight in newton. What is the reading of the machine when the lift is stationary? Take $g = 9.8 m s^{- 2}$

Zero

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50 N

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490 N

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500 N

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Solution

The correct option is C
490 N

Mass of the boy, $m = 50 k g$
Acceleration due to gravity, $g = 9.8 m s^{- 2}$
Let the weighing machine exert a normal force N on the boy in vertically upward direction.
As the lift is stationary, acceleration of the boy is zero.
From second law of motion, $N - m g = 0 \Rightarrow N = m g = 50 \times 9.8 = 490 N$
The machine measures this normal force. Thus, the correct choice (c).

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A boy of mass 50 kg is standing on a weighing machine placed on the floor of a lift. The machine reads his weight in newton. What is the reading of the machine when the lift is stationary? Take g=9.8 ms−2

A boy of mass 50 kg is standing on a weighing machine placed on the floor of a lift. The machine reads his weight in newton. What is the reading of the machine when the lift is stationary? Take $g = 9.8 m s^{- 2}$