A boy wants to climb down a rope. The rope can withstand a maximum tension equal to two thirds the weight of the boy. If g is the acceleration due to gravity, the minimum acceleration with which the boy should climb down the the rope is

\frac{g}{3}

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\frac{2 g}{3}

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g

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zero

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Solution

The correct option is A $\frac{g}{3}$
$\begin{matrix} Let us consider weight of man = ω = m g maximum tension = \frac{2}{3} ω \end{matrix}$
$\begin{matrix} Let a be acceleration of body we can write \end{matrix}$
$\begin{matrix} ω - \frac{2}{3} ω = m a \frac{m g}{3} = m a ∴ ω = m g a = \frac{g}{3} \end{matrix}$
$\begin{matrix} So, \frac{g}{3} be the minimum acceleration with which rope do not break. \end{matrix}$

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A boy wants to climb down a rope. The rope can withstand a maximum tension equal to two thirds the weight of the boy. If g is the acceleration due to gravity, the minimum acceleration with which the boy should climb down the the rope is

The correct option is A g3 Let us consider weight of man =ω=mg maximum tension =23ω Let a be acceleration of body we can write ω−23ω=mamg3=ma∴ω=mga=g3 So, g3 be the minimum acceleration with which rope do not break.