A buffer solution of pH=5.74 is to be prepared using CH3COOH and CH3COONa. Find the concentration of sodium acetate to be added to 0.01M solution of CH3COOH Ka(CH3COOH)=1.8×10−5
Take log(1.8)=0.26
A
0.1 M
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B
0.5 M
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C
1 M
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D
1.5 M
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Solution
The correct option is A 0.1 M pKa=−log(Ka)pKa=−log(1.8×10−5)=(5−0.26)pKa=4.74 pH=pKa+log[salt][acid]pH=pKa+log([CH3COONa][CH3COOH])5.74=4.74+log[CH3COONa]0.011=log[CH3COONa]0.01101=[CH3COONa]0.01[CH3COONa]=0.1M