A bulb is taken out at random from a box of 600 electric bulbs that contains 12 defective bulbs. Then the probability of a non-defective bulb is

0.02

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0.98

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0.5

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None

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Solution

The correct option is D 0.98
Total number of bulbs = 600
Total number of non-defective bulb = 600-12=588
P (non-defective bulbs) = $\frac{588}{600} = 0.98$

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A bulb is taken out at random from a box of 600 electric bulbs that contains 12 defective bulbs. Then the probability of a non-defective bulb is

The correct option is D 0.98Total number of bulbs = 600Total number of non-defective bulb = 600-12=588P (non-defective bulbs) = 588600=0.98

The correct option is D 0.98
Total number of bulbs = 600
Total number of non-defective bulb = 600-12=588
P (non-defective bulbs) = $\frac{588}{600} = 0.98$