A bullet initially moving with a velocity $20 m s^{- 1}$ strikes a target and comes to rest after penetrating a distance 10 m in the target. Calculate the retardation caused by the target.

2 m s^{- 2}

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5 m s^{- 2}

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10 m s^{- 2}

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20 m s^{- 2}

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Solution

The correct option is B $20 m s^{- 2}$
$u = 20 m / s, S = 10 m, v = 0$
Putting these values in $v^{2} = u^{2} + 2 a S$
$0 = 20^{2} + 2 a \times 10$
$a = - 20 m / s^{2}$
Hence, $Retardation = 20 m / s^{2}$

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