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Conservation of Momentum

A bullet of m...

Question

A bullet of mass $50 g$ moving with an initial velocity $100 m s^{- 1}$ , strikes a wooden block and comes to rest after penetrating a distance $2 c m$ in it. Calculate: (i) initial momentum of the bullet, (ii) final momentum of the bullet.

5

k g

m

s^{- 1}

5

k g

m

s^{- 1}

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5

k g

m

s^{- 1}

0

k g

m

s^{- 1}

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5

k g

m

s^{- 1}

2.5

k g

m

s^{- 1}

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2.5

k g

m

s^{- 1}

0

k g

m

s^{- 1}

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Solution

The correct option is B $5$ $k g$ $m$ $s^{- 1}$ , $0$ $k g$ $m$ $s^{- 1}$
Mass, $m = 50 g = 0.05 k g$
Initial velocity, $u = 100 m / s$
Final velocity, $v = 0$
(i) Initial momentum, $p_{i} = 0.05 \times 100 = 5 k g m / s$
(ii) Final momentum, $p_{f} = 0.05 \times 0 = 0$

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A bullet of mass 50g moving with an initial velocity 100ms−1, strikes a wooden block and comes to rest after penetrating a distance 2cm in it. Calculate: (i) initial momentum of the bullet, (ii) final momentum of the bullet.

The correct option is B 5 kg m s−1, 0 kg m s−1Mass, m=50 g=0.05 kgInitial velocity, u=100 m/sFinal velocity, v=0(i) Initial momentum, pi=0.05×100=5 kgm/s(ii) Final momentum, pf=0.05×0=0

A bullet of mass $50 g$ moving with an initial velocity $100 m s^{- 1}$ , strikes a wooden block and comes to rest after penetrating a distance $2 c m$ in it. Calculate: (i) initial momentum of the bullet, (ii) final momentum of the bullet.

The correct option is B $5$ $k g$ $m$ $s^{- 1}$ , $0$ $k g$ $m$ $s^{- 1}$
Mass, $m = 50 g = 0.05 k g$
Initial velocity, $u = 100 m / s$
Final velocity, $v = 0$
(i) Initial momentum, $p_{i} = 0.05 \times 100 = 5 k g m / s$
(ii) Final momentum, $p_{f} = 0.05 \times 0 = 0$