A bullet train starts from rest, and acquires a speed of $25 m s^{- 1}$ in $20 s$ . Assuming uniform acceleration calculate the distance covered by the train in $10 s$ .

1000 m

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200 m

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2000 m

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100 m

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Solution

The correct option is D $100 m$
Given:
initial velocity $u = 0 m s^{- 1}$ ,
final velocity $v = 20 m s^{- 1}$ ,
time $t = 10 s$

Let,
acceleration of train be $a$ ,
distance travelled $S$ .

We can calculate $a$ using, $a = \frac{v - u}{t} = \frac{20 - 0}{10} = 2 m s^{- 2}$

Now using, third equation of motion,
$v^{2} - u^{2} = 2 a S$
$20^{2} - 0^{2} = 2 \times 2 \times S$
or, $S = \frac{400}{4} = 100 m$

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A bullet train starts from rest, and acquires a speed of 25 ms−1 in 20 s. Assuming uniform acceleration calculate the distance covered by the train in 10 s.

The correct option is D 100 mGiven: initial velocity u=0 ms−1, final velocity v=20 ms−1, time t=10 s Let, acceleration of train be a, distance travelled S. We can calculate a using, a=v−ut=20−010=2 ms−2 Now using, third equation of motion, v2−u2=2aS 202−02=2×2×S or, S=4004=100 m

A bullet train starts from rest, and acquires a speed of $25 m s^{- 1}$ in $20 s$ . Assuming uniform acceleration calculate the distance covered by the train in $10 s$ .