A bus decelerating with 4m/s²changes its speed from 60 m s^-1 to a certain value in 5 s. The final speed is:

60 m/s

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30 m/s

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25 m/s

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40 m/s

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Solution

The correct option is D
40 m/s

Acceleration = - 4m/s²; Initial speed, u = 60 m s^-1

Time taken = 5s

Acceleration = change in velocity per unit time

a=v-u/t

v= u + at

v = 60 - 4 x 5 = 40 m/s

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Similar questions

An object covers half its journey with a speed of 40m/s and the other half with a speed of 60m/s. Find its average speed for the whole journey.

v = 6 t^{2} + 2 t m/s

3 sec

4 sec

150 m

50 m

25 m/s

x -

20 m/s

4 {m/s}^{2}

t = 5 sec

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