Question

A bus starting from rest moves with a uniform acceleration of $0.1m/s^2$ for 2 min. Find the distance traveled.

Answer 1

Step 1: Given data

The acceleration of the bus, $a=0.1m/s^2$.

The time traveled by bus is t = 2min = 120 seconds.

Initial speed, u = 0.

Step 2: Finding the distance

From newton's second equation of motion;

$s=ut+\frac{1}{2}a{t}^2$

Where "s" is the distance traveled by bus.

u = initial speed, a = acceleration, "t" is the time.

$$\begin{gathered} s=\left(0\times 2\right)+\frac{1}{2}(0.1)\times {\left(120\right)}^2 \\ =(0.5)\times (0.1)\times \left(14400\right). \end{gathered}$$

$s=720m.$

Therefore, the distance traveled by bus is $720m.$