Question

A bus starts from rest and attains a speed of $36km/h$ in $1minute$ while moving with uniform acceleration along a straight road. Calculate the acceleration of the bus.

Answer 1

Step 1 - Given:

Initial velocity $\left(u\right)$ =$0m/s$.

Final velocity $\left(v\right)$ = $36km/h$ = $36\times \frac{1000\left(m\right)}{3600\left(s\right)}=10m/s.$ $(1km=1000mand1hr=3600sec.)$

Time taken $\left(t\right)$ = $1minute$ = $60seconds$.

Step 2 - Calculation of acceleration:

Acceleration is defined as the rate of change of velocity.

The formula for acceleration is given by,

$acceleration=\frac{finalvelocity\left(v\right)-initialvelocity\left(u\right)}{timetaken\left(t\right)}$

$a=\frac{10-0}{60}=\frac{10}{60}=0.166m/s^2.$

Hence, the acceleration of the bus is $\mathbf{0}\mathbf{.}\mathbf{166}\mathit{m}\mathbf{/}{\mathit{s}}^{\mathbf{2}}\mathbf{.}$