A can do 15 th of a certain work in 2 days and B can do 23 rd of it in 8 days- In how much time can they together complete the work-

A's one day work = ( 15)2 = 110 B's one day work = ( 23)8 = 112 Therefore, ( A + B )'s one day work = 110 + 112 = 6 + 560 = ...

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Standard VII

Mathematics

Time and Work

A can do 15...

Question

$A$ can do $\frac{1}{5} t h$ of a certain work in $2$ days and $B$ can do $\frac{2}{3} r d$ of it in $8$ days. In how much time can they together complete the work.

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Solution

$A^{'} s$ one day work $= \frac{(\frac{1}{5})}{2} = \frac{1}{10}$
$B^{'} s$ one day work $= \frac{(\frac{2}{3})}{8} = \frac{1}{12}$
Therefore,
${(A + B)}^{'} s$ one day work $= \frac{1}{10} + \frac{1}{12} = \frac{6 + 5}{60} = \frac{11}{60}$
Hence, in $\frac{60}{11}$ days, they can complete the work together.

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A can do 15th of a certain work in 2 days and B can do 23rd of it in 8 days. In how much time can they together complete the work.

A′s one day work =(15)2=110B′s one day work =(23)8=112Therefore,(A+B)′s one day work =110+112=6+560=1160Hence, in 6011 days, they can complete the work together.

$A$ can do $\frac{1}{5} t h$ of a certain work in $2$ days and $B$ can do $\frac{2}{3} r d$ of it in $8$ days. In how much time can they together complete the work.