A car acquires a velocity of $72 k m h^{- 1}$ in 10 s starting from rest. Calculate the distance travelled in this time

100 km

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100 m

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10 km

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10 m

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Solution

The correct option is B 100 m
Average Velocity Equation
$v_{a v g} = \frac{v + v_{0}}{2}$
Where: $v_{a v g} = a v e r a g e v e l o c i t y$
$v_{0} = i n i t i a l v e l o c i t y$
$v = f i n a l v e l o c i t y$

$v = 72 k m / h = \frac{72000}{3600} m / s = 20 m / s$
$v_{a v g} = \frac{0 + 20}{2} = 10 m / s$
Distance travelled (D) = Average velocity * time
so, $D = 10 \times 10 = 100 m$
Answer (B) 100m

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