Question

A car battery of emf 12 V and internal resistance $5\times {10}^{-2}\Omega$ receives a current of 60 $\dot{A}$ from external source, then terminal voltage of battery is :

• A. 12 V
• B. 9 V
• C. 15 v
• D. 20 V

Answer 1

The correct option is C 15 v

Given data,

Battery of emf$=12V$

Internal resistance $R=5\times {10}^{-2}$

Current $I-{60}^{\circ }A$

Find Terminal voltage $V=?$

$V=E+IR$

$=12+60\times 5\times {10}^{-2}$

$=12+3$

$=15V$