A car, having acceleration $1 m s^{- 2}$ , is moving with an initial velocity $10 m / s$ and it stops after 10 seconds as the driver applied brakes. Find the distance travelled by the car.

30 m

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40 m

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50 m

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60 m

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Solution

The correct option is B 50 m
As we know, $v^{2} = u^{2} - 2 a S$
$S = \frac{u^{2}}{2 a} = \frac{10^{2}}{2 \times 1} = 50 m ∵ final velocity (v) = 0$

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A car, having acceleration 1ms−2, is moving with an initial velocity 10m/s and it stops after 10 seconds as the driver applied brakes. Find the distance travelled by the car.

The correct option is B 50 mAs we know, v2=u2−2aSS=u22a=1022×1=50 m ∵final velocity(v)=0

A car, having acceleration $1 m s^{- 2}$ , is moving with an initial velocity $10 m / s$ and it stops after 10 seconds as the driver applied brakes. Find the distance travelled by the car.

The correct option is B 50 m
As we know, $v^{2} = u^{2} - 2 a S$
$S = \frac{u^{2}}{2 a} = \frac{10^{2}}{2 \times 1} = 50 m ∵ final velocity (v) = 0$