A car moves at a constant speed on a rod as shown in figure. The normal force by the rod on the car is $N_{A}$ and $N_{B}$ when it is at the points $A$ and $B$ respectively.

N_{A} = N_{B}

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N_{A} > N_{B}

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N_{A} < N_{B}

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insufficient information to decide the relation of

N_{A}

and

N_{B}

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Solution

The correct option is B $N_{A} < N_{B}$
At Point A,
$m g - N_{A} = \frac{M V^{2}}{r_{1}}$

$\Rightarrow N_{A} = m g - \frac{M V^{2}}{r_{1}}$

At Point B,
$m g - N_{B} = \frac{M V^{2}}{r_{2}}$

$\Rightarrow N_{B} = m g - \frac{M V^{2}}{r_{2}}$

$r_{2} > r_{1}$

$∴ N_{A} < N_{B}$

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A car moves at a constant speed on a rod as shown in figure. The normal force by the rod on the car is NA and NB when it is at the points A and B respectively.

The correct option is B NA<NBAt Point A,mg−NA=MV2r1⇒NA=mg−MV2r1At Point B,mg−NB=MV2r2⇒NB=mg−MV2r2r2>r1∴NA<NB

A car moves at a constant speed on a rod as shown in figure. The normal force by the rod on the car is $N_{A}$ and $N_{B}$ when it is at the points $A$ and $B$ respectively.

The correct option is B $N_{A} < N_{B}$
At Point A,
$m g - N_{A} = \frac{M V^{2}}{r_{1}}$

$\Rightarrow N_{A} = m g - \frac{M V^{2}}{r_{1}}$

At Point B,
$m g - N_{B} = \frac{M V^{2}}{r_{2}}$

$\Rightarrow N_{B} = m g - \frac{M V^{2}}{r_{2}}$

$r_{2} > r_{1}$

$∴ N_{A} < N_{B}$