A car of mass 1 metric ton starts from rest and accelerates at a speed of 72km/h in 20 seconds. It the moves with a constant velocity of 80 sec and is brought to rest in next 10 sec.What is the total distance covered by the car in the entire journey

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Solution

Dear student,
$H e r e, m = 1 m e t r i c t o n = 1000 k g u = 0, v = 72 k m / h = 72 \times \frac{1000}{60 \times 60 s} = 20 m / s t = 20 s (i) F r o m 0 t o 20 s e c a = \frac{v - u}{t} = \frac{20 - 0}{20} = 1 m / s^{2} D i s \tan c e c o v e r e d i n t h i s p a r t = 0.5 \times a \times t^{2} = 0.5 \times 1 \times 20^{2} = 200 m (i i) F r o m 20 s e c t o 100 s e c D i s \tan c e c o v e r e d w i t h c o n s \tan t v e l o c i t y = 20 \times 80 = 1600 m (i i i) F r o m 100 t o 110 s e c a = \frac{v - u}{t} = \frac{0 - 20}{10} = - 2 m / s^{2} S = \frac{u^{2}}{2 a} = \frac{400}{2 \times 2} = 100 m (a s v = 0) S o t o t a l d i s \tan c e = 200 + 1600 + 100 = 1900 m$
Regards

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