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Question

# A car starts from rest and moves along the x-axis with constant acceleration 5ms−2 for 8 seconds. If it then continues with constant velocity, what distance will the car cover in 12 seconds since it started from rest?

A
320 m
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B
160 m
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C
480 m
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D
720 m
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Solution

## The correct option is A 320 ms1=ut+(1/2)at2 =0+12×5×82 =160 m.The velocity attained in 8 seconds is given byv=u+at =0+5×8=40 m/s.The distance traveled in the next 4 seconds is s2=40×4=160 m.So, the total distance traveled by the car is s1+s2=160+160=320 m

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