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Question

A car starts from rest and moves along the x-axis with constant acceleration 5ms2 for 8 seconds. If it then continues with constant velocity, what distance will the car cover in 12 seconds since it started from rest?

A
320 m
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B
160 m
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C
480 m
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D
720 m
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Solution

The correct option is A 320 m
s1=ut+(1/2)at2
=0+12×5×82
=160 m.
The velocity attained in 8 seconds is given by
v=u+at
=0+5×8=40 m/s.
The distance traveled in the next 4 seconds is
s2=40×4=160 m.
So, the total distance traveled by the car is s1+s2=160+160=320 m

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