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Question

A car starts from rest and moves along the x-axis with constant acceleration of 5 ms2 for 8 seconds. If it then continues with constant velocity, what distance will the car cover in 12 seconds since it started from the rest?

A
300 m
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B
310 m
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C
320 m
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D
400 m
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Solution

The correct option is C 320 m
Given,
initial velocity, u=0,
acceleration, a=5 ms2 and
time taken, t=8 s.

Let s1 be the distance travelled and v be the final velocity.

From second equation of motion, s=ut+12at2
s1=0×8+12×5×82=160 m

From first equation of motion, v=u+atv=0+5×8=40 ms1

Now we have to find the distance covered in time t=12 s

We know, distance=speed×time.
As the speed is constant, after 8 s. i.e, speed =40 ms1, therefore in the remaining 4 s its covers distance, s2=40×4=160 m
Thus total distance covered in 12 s, s1+s2=160+160=320 m

Hence the correct option is (C)


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