Question

# Question 15 A car starts from rest and moves along the x-axis with constant acceleration  5 ms−2 for 8 seconds. If it then continues with constant velocity, what distance will the car cover in 12 seconds since it started from the rest?

Solution

## Given, initial velocity, u=0, acceleration, a=5 ms−2 and time taken, t=8 s. Let s1 be the distance travelled and v be the final velocity. From second equation of motion, s=ut+12at2 ⇒s1=0×8+12×5×82=160 m From first equation of motion, v=u+at⇒v=0+5×8=40 ms−1 Now we have to find the distance covered in time t=12 s We know, distance=speed×time. As the speed is constant, after 8 s. i.e, speed =40 ms−1, therefore in the remaining 4 s its covers a distance s2=40×4=160 m Thus total distnace covered in 12 s, s1+s2=160+160=320 mPhysicsNCERT ExemplarStandard IX

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