CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

Question 15
A car starts from rest and moves along the x-axis with constant acceleration  5 ms2 for 8 seconds. If it then continues with constant velocity, what distance will the car cover in 12 seconds since it started from the rest?


Solution

Given, initial velocity, u=0, acceleration, a=5 ms2 and time taken, t=8 s.
Let s1 be the distance travelled and v be the final velocity.
From second equation of motion, s=ut+12at2
s1=0×8+12×5×82=160 m
From first equation of motion, v=u+atv=0+5×8=40 ms1

Now we have to find the distance covered in time t=12 s
We know, distance=speed×time.
As the speed is constant, after 8 s. i.e, speed =40 ms1, therefore in the remaining 4 s its covers a distance s2=40×4=160 m
Thus total distnace covered in 12 s, s1+s2=160+160=320 m

Physics
NCERT Exemplar
Standard IX

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
Same exercise questions
View More


similar_icon
People also searched for
View More



footer-image