A car starts from rest and moves along the x axis with constant acceleration 5 m per second for 8 seconds it then continuous with constant velocity what distance will the car cover in 12 seconds since it started from the rest

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Solution

V=u+at

v=0+5m/s^28

v=40m/s
constant velocity=40m/s

distance covered in the first 8 sec =

S=1/2at^2=160m.

distance covered in the last 4 sec=const.

speedtime=40m/s4=160m

total distance covered in 12 sec= 160+160= 320m

So Distance covered is 320m

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A motor car starts from rest and accelerates uniformly for 10 seconds to a velocity of 40 m/s, it then runs at a constant speed and is finally brought to rest in 40 m with a constant acceleration.Total distance covered is 640 meters. Find acceleration, retardation and total time taken.

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A car starts from rest and moves along the x axis with constant acceleration 5 m per second for 8 seconds it then continuous with constant velocity what distance will the car cover in 12 seconds since it started from the rest

V=u+at v=0+5m/s^2*8 v=40m/s constant velocity=40m/s distance covered in the first 8 sec = S=1/2a*t^2=160m. distance covered in the last 4 sec=const. speed*time=40m/s*4=160m total distance covered in 12 sec= 160+160= 320m So Distance covered is 320m

V=u+at

v=0+5m/s^28

v=40m/s
constant velocity=40m/s

distance covered in the first 8 sec =

S=1/2at^2=160m.

distance covered in the last 4 sec=const.

speedtime=40m/s4=160m

total distance covered in 12 sec= 160+160= 320m

So Distance covered is 320m