Question

# A car travels $15m$ in $3s$ and then another $15m$ in $2s$. What is the avergae speed of the car?

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Solution

## Step 1: GivenDistance traveled, ${d}_{1}={d}_{2}=15m$Time taken, ${t}_{1}=3s\phantom{\rule{0ex}{0ex}}{t}_{2}=2s$Step 2: Formula used$Averagespeed=\frac{Totaldis\mathrm{tan}ce}{Totaltime}$Step 3: Determine the average speed$Averagespeed=\frac{Totaldis\mathrm{tan}ce}{Totaltime}\phantom{\rule{0ex}{0ex}}=\frac{{d}_{1}+{d}_{2}}{{t}_{1}+{t}_{2}}\phantom{\rule{0ex}{0ex}}=\frac{15+15}{2+3}\phantom{\rule{0ex}{0ex}}=\frac{30}{5}\phantom{\rule{0ex}{0ex}}=6m/s$Therefore, the average speed of the car is $6m/s$.

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