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Question

A car travels a distance of 900 km with a certain speed. If after travelling half the distance, the speed is increased by 15 km/h, time required to travel 900 km is reduced by 112 hours. Find the original speed of the car.

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Solution

Let T1= Time taken by car with original speed=900v

T2= Time taken by car when speed is changed after half distance =450v+45015+v

Given,
T1T2=32900v(450v+45015+v)=322×450×15=3×v×(v+15)v2+15v4500=0v=15,30

Therefore, answer is 15 km/hr


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