Question

A car travels with a velocity $10{ms}^{-1}$ and accelerates at $5{ms}^{-2}$. Calculate the final velocity when it has travelled $30m$.

Answer 1

Step 1, Given data

Initial Velocity (u) = 10 $m/sec$

Acceleration (a) = 5 $m/se{c}^2$

Distance (s) = 30 m

Final velocity (v) = ??

Step 2, Finding the final velocity

Using Third equation Motion,

$v^2=u^2+2as$

Putting all the values

$v^2={10}^2+2\times 5\times 30$

Or, $v^2=100+300$

Or, $v^2=400$

Or, v = $\sqrt{400}$

Therefore, v = 20 $m/sec$

Hence the final velocity is 20 m/s