A charge ‘Q’ is uniformly distributed on the surface of a spherical conductor. In order to calculate the Electric field because of it, one has to take infinitesimal elements of charges and integrate. This is because

Electrostatic force between two charges is a central force.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Electrostatic force is dependent upon the medium in which the charges are located.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Electrostatic force can only be utilized for point charges.

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Electrostatic force varies with inverse of distance squared.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
Electrostatic force can only be utilized for point charges.

Electrostatic force between two charges at restis given by Coulomb’s law. Coulomb’s law is valid only for point charges. In order to calculate the net field due to a continuous charge distribution at any point,

We need to choose infinitesimal elements,

Treat them as point charges and

Calculate electrostatic force.

Integration is used to add the fields due to all such charges.

Suggest Corrections

Similar questions

A charge ‘Q’ is uniformly distributed on the surface of a spherical conductor. In order to calculate the Electric field because of it, one has to take infinitesimal elements of charges and integrate. This is because

Q. The electrostatic force on a charge due to another charge is F. In presence of one more charge, what would be the electrostatic force on the first charge due to second charge?

Q. Assertion :The magnitude of the electrostatic force of interaction between two point charges is directly proportional to the scalar multiplication of the magnitudes of charges and inversely proportional to the square of the distance between them. Reason: Electrostatic force is analogous to gravitational force

Q. The Electrostatic Force between two charges is 4 N. If one charge has a value of 5

μ

C and is 2 cm from the second charge, find the new electrostatic force if the second charge is moved 2 cm further away from the first charge.

Two bodies have equal charge

q

, where each is charged with two electrons. One electron is transferred from the first body to the second so that one body has one excess electrons and other has three excess electrons while maintaining the distance between the charges. Which of the following statements are correct?

I.The amount of electrostatic charge has decreased
II.The electrostatic force between the pith balls has decreased
III.Both the electrostatic charge and force have decreased

Join BYJU'S Learning Program