A charged particle with velocity 2×103m/s passes undeflected through electric and magnetic field. Magnetic field is 1.5 tesla. The electric field intensity would be
A
2×103N/C
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B
1.5×103N/C
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C
3×103N/C
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D
4/3×10−3N/C
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Solution
The correct option is D3×103N/C E=vB =2×103×1.5 =3×103V/m