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Standard XII

Physics

Two Parallel Currents

A charged par...

Question

A charged particle with velocity $2 \times 10^{3} m / s$ passes undeflected through electric and magnetic field. Magnetic field is 1.5 tesla. The electric field intensity would be

2 \times 10^{3} N / C

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1.5 \times 10^{3} N / C

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3 \times 10^{3} N / C

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4 / 3 \times 10^{- 3} N / C

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Solution

The correct option is D $3 \times 10^{3} N / C$
$E = v B$
$= 2 \times 10^{3} \times 1.5$
$= 3 \times 10^{3} V / m$

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A charged particle with velocity 2×103m/s passes undeflected through electric and magnetic field. Magnetic field is 1.5 tesla. The electric field intensity would be

The correct option is D 3×103N/CE=vB=2×103×1.5=3×103V/m

A charged particle with velocity $2 \times 10^{3} m / s$ passes undeflected through electric and magnetic field. Magnetic field is 1.5 tesla. The electric field intensity would be

The correct option is D $3 \times 10^{3} N / C$
$E = v B$
$= 2 \times 10^{3} \times 1.5$
$= 3 \times 10^{3} V / m$