Question

A child has a die whose six faces show the letters as given below :

$ABCDEA$. The die is thrown once. What is the probability of getting

i) $A$?

ii) $D$?

Answer 1

Total no. of faces on the die $=6$

No. of faces having $A$ on it $=2$

No. of faces having $D$ on it $=1$

Therefore,

$\left(i\right)P\left(\text{getting A}\right)=\frac{\text{No. of faces having A}}{\text{Total no. of faces}}=\frac{2}{6}=\frac{1}{3}$
$\left(ii\right)P\left(\text{getting D}\right)=\frac{\text{No. of faces having D}}{\text{Total no. of faces}}=\frac{1}{6}$