A circus tent is cylindrical to a height of 3 m and conical above it. If its base radius is 52.5 m and the slant height of the conical portion is 53 m, find the area of canvas needed to make the tent. $[T a k e π = \frac{22}{7}]$

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Solution

Height = h = 3 metres

Slant height = l = 53 metres

Radius = r = 52.5 metres

Area of canvas required = C.S.A of cone = $π r l$
= $\frac{22}{7}$ × 52.5 × 53
= 8745 m²

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A circus tent is cylindrical to a height of 3 m and conical above it. If its base radius is 52.5 m and the slant height of the conical portion is 53 m, find the area of canvas needed to make the tent. $[T a k e π = \frac{22}{7}]$

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Q. A circus tent is cylindrical to a height of 3 metres and conical above it. If its diameter is 105 m and the slant height of the conical portion is 53 m, calculate the length of the canvas 5 m wide to make the required tent.

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A circus tent is cylindrical to a height of 3 m and conical above it. If its base radius is 52.5 m and the slant height of the conical portion is 53 m, find the area of canvas needed to make the tent. [Take π=227]

Height = h = 3 metres Slant height = l = 53 metres Radius = r = 52.5 metres Area of canvas required = C.S.A of cone = πrl = 227 × 52.5 × 53 = 8745 m²

A circus tent is cylindrical to a height of 3 m and conical above it. If its base radius is 52.5 m and the slant height of the conical portion is 53 m, find the area of canvas needed to make the tent. $[T a k e π = \frac{22}{7}]$

Height = h = 3 metres

Slant height = l = 53 metres

Radius = r = 52.5 metres

Area of canvas required = C.S.A of cone = $π r l$
= $\frac{22}{7}$ × 52.5 × 53
= 8745 m²