A cistern of capacity 8000 litres measures externally 3.3 m by 2.6 m by 1.1 m and its walls are 5 cm thick. The thickness of the bottom is:

90 cm

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1 dm

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1 m

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0.9 m

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Solution

The correct option is B
1 dm

Let the thickness of the bottom b `x' cm

Then, [(330 -- 10) $\times$ (260 -- 10) $\times$ (110 - x) = 8000 $\times$ 1000

$\Leftrightarrow$ 320 $\times$ 250 $\times$ (110 -- x) = 8000 $\times$ 1000 $\Leftrightarrow$ (110 -- x) = $\frac{8000 \times 1000}{320 \times 250}$ = 100

$\Leftrightarrow$ x = 10 cm = 1 dm

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A cistern of capacity 8000 litres measures externally 3.3 m by 2.6 m by 1.1 m and its walls are 5 cm thick. The thickness of the bottom is:

The correct option is B 1 dm Let the thickness of the bottom b `x' cm Then, [(330 -- 10) × (260 -- 10) × (110 - x) = 8000 ×1000 ⇔ 320 × 250 × (110 -- x) = 8000 × 1000 ⇔ (110 -- x) = 8000×1000320×250 = 100 ⇔ x = 10 cm = 1 dm