A cistern of capacity 8000 litres measures externally 3.3 m by 2.6 m by 1.1 m and its walls are 5 cm thick. The thickness of the bottom is:

90 cm

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1 dm

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1 m

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1.1 m

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0.9 m

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Solution

The correct option is B
1 dm

Let the thickness of the bottom b `x' cm

Then, $[(330 - 10) \times (260 - 10) \times (110 - x) = 8000 \times 1000$

$\Leftrightarrow 320 \times 250 \times (110 - x)$ = $8000 \times 1000$ $\Leftrightarrow (110 - x) = \frac{8000 \times 1000}{320 \times 250} = 100$

$\Leftrightarrow x = 10 c m = 1 d m$

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A cistern of capacity 8000 litres measures externally 3.3 m by 2.6 m by 1.1 m and its walls are 5 cm thick. The thickness of the bottom is:

The correct option is B 1 dm Let the thickness of the bottom b `x' cm Then,[(330−10)× (260−10)× (110−x)=8000×1000 ⇔320×250×(110−x) =8000×1000 ⇔(110−x)=8000×1000320×250=100 ⇔x=10cm=1dm