A coil 2.0 cm in diameter has 300 truns. If the coil carries a current of 10mA and lies in a magnetic field 5×10−2T, the maximum torque experienced by the coil is :
A
4.7×10−5N-m
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B
5×10−4N-m
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C
5×10−5N-m
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D
5×10−6N-m`
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Solution
The correct option is A4.7×10−5N-m area=πd24=π4×2×10−4=π×10−4M=300I=10×10−3AB=5×10−2Tτ=MBIA=300×5×10−2×10×10−3×π×10−4=4.7×10−5 N-m