The correct option is
D hydrogen
Since compound ′A′ of Boron reacts with NMe3 to form an adduct ′B′. Thus compound ′A′ is lewis acid. Hydrolysis of ′B′ gives an acid ′C′ and hydrogen gas.
Diborane (A) B2H6+2NMe3⟶2BH3⋅NMe3 Adduct (B)
BH3⋅NMe3+3H2O⟶H3BO3+NMe3+6H2 Boric Acid (C)