A compound 'X' reacts with conc. Sulphuric acid to give an alkene. The alkene reacts with bromine and subsequent treatment of the product with alcoholic KOH yields propyne. The formula of the compound is

$C H_{3} C H_{2} C H_{2} B r$

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$C H_{3} C H_{2} C H_{2} O H$

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$C H_{3} C H_{2} O H$

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$C H_{3} O H$

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Solution

The correct option is B
$C H_{3} C H_{2} C H_{2} O H$

Compound is 3 carbon one

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A compound 'X' reacts with conc. Sulphuric acid to give an alkene. The alkene reacts with bromine and subsequent treatment of the product with alcoholic KOH yields propyne. The formula of the compound is

The correct option is B CH3CH2CH2OH Compound is 3 carbon one

The correct option is B
$C H_{3} C H_{2} C H_{2} O H$

Compound is 3 carbon one